FAQ: Advanced Objects - Factory Functions

This community-built FAQ covers the “Factory Functions” exercise from the lesson “Advanced Objects”.

Paths and Courses
This exercise can be found in the following Codecademy content:

Web Development

Introduction To JavaScript

FAQs on the exercise Factory Functions

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I think i’m missing the point of this exercise. I have it all working :

// step 1
const robotFactory = (model, mobile) => {
  return {
    model: 'model',
    mobile: 'mobile',
    beep() {
    	console.log('Beep Boop');
// step 2
const tinCan = robotFactory('P-500', true);

// step 3

The results spits out “Beep Boop”. My question is : Where are the (P-500, true) values from step 2.? What was I supposed to learn from this?

I also don’t get what that “true” of the second argument in “step 2” is for.
I changed to “false” to test out, and tinCan.beep(); still works.

If you poll their values, they will be found…

console.log(tinCan.model, tinCan.mobile, tinCan.beep());
1 Like

Hey, in this exercise it is asked of us to use const to declare the monster function, and i tried to use function out of curiosity, and it’s working.
Hence my question : is there any reason to use either one rather than the other ?

Concerning the lesson (not the exercise), what happens to the “catchPhrase” parameter to “monsterFactory”?

catchPhrase is not a property of the monster object, but there seems to be a copy maintained somewhere because you can create two monster objects with different catchPhrases and the scare() method works as expected.

Thanks for any explanation you can supply!

When I attempt to use an old-fashioned function declaration to create a factory function, I’m able to complete the assignment so that all the checkboxes pass in the Codecademy exercise. However, after the console prints “Beep Boop,” it also creates a new line that returns “undefined.”

Is it improper to create an object in this manner? Is there something else that I have included or excluded that is causing this extra line to print? Please see below for the code I used to complete the assignment:

function robotFactory(model, mobile) {
  return {
    model: model, 
    mobile: mobile,
    beep() {console.log("Beep Boop\n")}

const tinCan = robotFactory('P-500', true);


The method is logging, so when you log it again you get the return from console.log() which is undefined. Lesson here, log once. Call the method without logging.

1 Like

That makes perfect sense. Thanks, Roy!

1 Like

That did not answer my question. Regardless of what kind of object it is, why does catchPhrase persist? Knowing a little more about JS now, I would say it persists because it’s in a closure. In this case, catchPhrase acts like a property of the created object.



Would this code be any good? (Not for the exercise, just for knowledge)

let monsterFactory = (model, mobile){
return name = {
model: model
mobile: mobile
console.log("Beep Boop");

I think it would be just better to assign an object directly from the factory function. This code may seem stupid and wrong, but I’m here to find out if it is.

We cannot make an assignment in a return statement.

Be aware of the syntax of plain objects… Comma separated properties.

Ditto what @mtf said, and you can declare a function either with the function key word or with let, const, var and the arrow syntax. Unless you are planning to change the properties of your ‘monsters’ dynamically with code later in your program, I would use const to declare the function, or just use the function key word.

function monsterFactory(model, mobile) {
  // function body to 'return' a monster object


const monsterFactory = (model, mobile) => {
  // function body to 'return' a monster object