- Return the total number of apps whose name begin with the letter ‘A’.
SELECT COUNT(*) FROM fake_apps;
WHERE name LIKE ‘A%’;
I repeatedly receive a return of: COUNT(*) ===>>> 200 from the system,
Is anyone having the same type of issue?
SELECT COUNT(*) FROM fake_apps;
WHERE name LIKE ‘A%’;
I repeatedly receive a return of: COUNT(*) ===>>> 200 from the system,
Is anyone having the same type of issue?
You should only put a semicolon at the very end of your query.