Extra Credit : Adding another ship


#1

How do I add another ship without overlapping it? I would assume I'd use the same randit function, but
am not sure where and how to write the non-overlapping clause.

from random import randint

board = []

for x in range(5):
    board.append(["O"] * 5)

def print_board(board):
    for row in board:
        print " ".join(row)

print "Let's play Battleship!"
print_board(board)

def random_row(board):
    return randint(0, len(board) - 1)

def random_col(board):
    return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
ship_2_row = random_row(board)
ship_2_col = random_col(board)

print ship_row
print ship_col

# Everything from here on should go in your for loop!
# Be sure to indent four spaces!
for turn in range(4):
    guess_row = int(raw_input("Guess Row:"))
    guess_col = int(raw_input("Guess Col:"))

    if guess_row == ship_row and guess_col == ship_col:
        print "Congratulations! You sunk my battleship!"
        board[guess_row][guess_col] == "X"
        break
    else:
        if (guess_row < 0 or guess_row > 4) or (guess_col < 0 or guess_col > 4):
            print "Oops, that's not even in the ocean."
            if turn == 3:
                print "Game Over"
        elif(board[guess_row][guess_col] == "X"):
            print "You guessed that one already."
            if turn == 3:
                print "Game Over"
        else:
            print "You missed my battleship!"
        board[guess_row][guess_col] = "X"
        print "Turn", turn+1
        if turn == 3:
            print "Game Over"
    print_board(board)

#2

Try describing the behaviour you want in a google search
https://www.google.com/search?q=python+choose+n+random
You might also just consider how you'd select two outcomes from a 6-sided dice


#3

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