Exercise 9 Functions with two parameters


#1


Okay can someone explain how this exercise isn't broken? The instructions call for you to put in any value that you wish for length and width of the box, yet the error tells me that I am incorrect because it doesn't return (4) for a width of 1 and a length of 1.

https://www.codecademy.com/en/courses/javascript-beginner-en-6LzGd/2/1?curriculum_id=506324b3a7dffd00020bf661#


// Write your function starting on line 3

var perimeterBox = function(length, length, width, width) {
    return length + length + width + width;
};
perimeterBox(48, 48, 84, 84);


#2

Your problem is you have an extra length and width in your function() you just need function (length, width) and it should work for you!


#3

@cactusking0
You should understand the working of the parameter in a function definition

Please read the Function talk
and concentrate on
- parameter
- argument
- calling a function
- usage of the return statement

the FUNCTION talk

var myFunc = function( param1, param2) {
       //Begin of  anonymous FUNCTION-BODY
       //VARIABLE -myFunc- has an -anonymous function- assigned
       //this -anonymous function- has 2 PARAMETERS param1 and param2
       //param1 and param2 PARAMETERS are used 
       //as -local- VARIABLES throughout the FUNCTION-BODY

      console.log( param1 + " and " + param2 ) ;

      //End of anonymous FUNCTION-BODY
};

If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren");

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

function with 1 parameter using return-statement

var myFunction = function( param1 ) {
       //Begin of FUNCTION-BODY
       //myFunction =function= has 1 PARAMETER param1
       //this param1 PARAMETER is used as a -local- VARIABLE
       //throughout the FUNCTION-BODY

      return param1;

      //End of FUNCTION-BODY
      };

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 );

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

var theResult = myFunction( 4 );
console.log( theResult );

OR directly

console.log( myFunction( 4 ) );

#4

Thanks a lot, man. That was easy enough to understand even for a dumb dumb like me.


#5

I hate to say this but none of that made any sense. I don't know really too much. Could you make it into laymen terms? I really don't understand much of that. I got it to work finally, but I still don't understand your....comment (I don't know if it was an answer a question).


#6

Nay, don't call your self dumb. It is a simple mistake and @leonhard.wettengmx.n does a great job explaining why it has to be that way in the above post ^ hope the rest of your coding goes well! :smiley:


#7

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