Error: name 'operator' is not defined

[sfranzi]

Hi,

I am receiving the following error:

Traceback (most recent call last):
File “CelebrityMatch.py”, line 70, in
sorted_result = sorted(compared_results.items(), key=operator.itemgetter(1))
NameError: name ‘operator’ is not defined

Please help.

Here is my code without the twitter and PI credentials:

def analyze(handle):
import sys
import operator
import requests
import json
import twitter
from watson_developer_cloud import PersonalityInsightsV2 as PersonalityInsights

twitter_consumer_key = ''
twitter_consumer_secret = ''
twitter_access_token = ''
twitter_access_secret = ''

twitter_api=twitter.Api(consumer_key=twitter_consumer_key,
                         consumer_secret=twitter_consumer_secret,
                         access_token_key=twitter_access_token,
                         access_token_secret=twitter_access_secret)

statuses = twitter_api.GetUserTimeline(screen_name=handle, count=200, include_rts=False)

text = ""

for status in statuses: 
  if (status.lang == 'en'):
    text += status.text.encode('utf-8')

#The IBM Bluemix credentials for Personality Insights
pi_username = ''
pi_password = ''

personality_insights = PersonalityInsights(username=pi_username, password=pi_password)

pi_result = personality_insights.profile(text)
return pi_result

def flatten(orig):
data = {}
for c in orig[‘tree’][‘children’]:
if ‘children’ in c:
for c2 in c[‘children’]:
if ‘children’ in c2:
for c3 in c2[‘children’]:
if ‘children’ in c3:
for c4 in c3[‘children’]:
if (c4[‘category’] == ‘personality’):
data[c4[‘id’]] = c4[‘percentage’]
if ‘children’ not in c3:
if (c3[‘category’] == ‘personality’):
data[c3[‘id’]] = c3[‘percentage’]
return data

def compare(dict1, dict2):
compared_data = {}
for keys in dict1:
if dict1[keys] != dict2[keys]:
compared_data[keys]=abs(dict1[keys] - dict2[keys])
return compared_data

user_handle= “@SeFranzi”
celebrity_handle= “@IBM”

user_result = analyze(user_handle)
celebrity_result = analyze(celebrity_handle)

user= flatten(user_result)
celebrity= flatten(celebrity_result)

compared_results= compare(user, celebrity)

sorted_result = sorted(compared_results.items(), key=operator.itemgetter(1))

for keys, value in sorted_result[:5]:
print keys,
print(user[keys]),
print (’->’),
print (celebrity[keys]),
print (’->’),
print (compared_results[keys])