Eleccion1 es igual a piedra

#1

var usuarioElige = prompt("¿piedra, papel o tijera?")
console.log("piedra")
console.log("papel")
}else{
console.log("tijera")
}

var comparar = function (eleccion1,eleccion2){
if (eleccion1 === eleccion2){
return("¡Es un empate!")
console.log("Papel gana")
console.log("Tijeras ganan")
} else {
console.log("Piedra gana")}}

Me da este error:¡Uy! Probá otra vez. La sentencia no da como resultado un ganador

#2

The Math.random() method will deliver a number with a value
in the range of 0_(included)_ upontill 0.9999_(1 excluded)_.

As you will have to divide the number range form 0_(inclusive)_ to 0,9999_(so 1 excluded)_
into 3 equal partitions
we have to use an if else-if else statement.
The if else-if else skeleton looks like:

``````    if (conditionA) {
//conditionA is true
} else if (conditionB) {
//conditionA is false
//conditionB is true
} else {     // <=== !! Takes NO condition-statements !!
//conditionA is false
//conditionB is false
}``````

following the Instructions the conditions would be:

1. If computerChoice is between 0 and 0.33, make computerChoice equal to "rock".
( 0 <= computerChoice && computerChoice <= 0.33) which we capture at the IF using
( computerChoice <= 0.33)

2. If computerChoice is between 0.34 and 0.66, make computerChoice equal to "paper".
( 0.33 < computerChoice && computerChoice < 0.67) which we capture at the ELSE IF as
( computerChoice < 0.67 )

3. If computerChoice is between 0.67 and 1, make computerChoice equal to "scissors".
( 0.67 <= computerChoice && computerChoice < 1) , you reached the ELSE level
you can asume that computerChoice is greater equal to 0.67,
the ELSE does NOT take a condition, just write your code.

and then you will have to create.....