Dataframe number count


#1



difference_1 = pd.DataFrame(difference)
print(difference)

       0
0      1
1      1
2      1
3      0
4      2
5      2
6      0
7      1
8      0
9      0
10     0
11     0
12     1
13     0
14     0
15     0
16     1
17     0
18     1
19     0
20     1
21     1
22     0
23     1
24     0
25     1
26     1
27     0
28     1
29     1
...   ..
13873  1
13874  1
13875  1
13876  2
13877  0
13878  1
13879  1
13880  0
13881  1
13882  1
13883  0
13884  0
13885  1
13886  1
13887  1
13888  0
13889  2
13890  1
13891  1
13892  1
13893  0
13894  0
13895  2
13896  2
13897  0
13898  0
13899  0
13900  0
13901  2
13902  1

[13903 rows x 1 columns]

I have a dataframe above. How do I count the number of times a number greater than or equal to to occurs?