Credit Card Checker: Solution

ochomozone · March 14, 2023, 4:51am

Here is my solution for the credit checker project on the javascript course.
Feedback is highly appreciated.

gist.github.com

https://gist.github.com/codecademydev/52ea632deebb7b47b01368d66160047e

main.js

// All valid credit card numbers
const valid1 = [4, 5, 3, 9, 6, 7, 7, 9, 0, 8, 0, 1, 6, 8, 0, 8];
const valid2 = [5, 5, 3, 5, 7, 6, 6, 7, 6, 8, 7, 5, 1, 4, 3, 9];
const valid3 = [3, 7, 1, 6, 1, 2, 0, 1, 9, 9, 8, 5, 2, 3, 6];
const valid4 = [6, 0, 1, 1, 1, 4, 4, 3, 4, 0, 6, 8, 2, 9, 0, 5];
const valid5 = [4, 5, 3, 9, 4, 0, 4, 9, 6, 7, 8, 6, 9, 6, 6, 6];

// All invalid credit card numbers
const invalid1 = [4, 5, 3, 2, 7, 7, 8, 7, 7, 1, 0, 9, 1, 7, 9, 5];
const invalid2 = [5, 7, 9, 5, 5, 9, 3, 3, 9, 2, 1, 3, 4, 6, 4, 3];

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micro5479526513 · March 20, 2023, 7:41pm

Hi and thanks for sharing your solutions. I gained some insight on how to apply the array functions and methods to this program. I am just a bit confused as to why all of the digits were doubled. I understood the instructions to state that every other digits from the right should be doubled. Does [every other] mean to skip one digit in the iteration? For instance (i-2). Thanks for your assistance

ochomozone · April 18, 2023, 6:57am

From this code:
if (((i - arr.length) % 2) === 0)
{ newArray.push((arr[i]) * 2);} else {newArray.push((arr[i]) );}
};

you can see that I’m only doubling digits with an even index.

micro5479526513 · April 18, 2023, 4:08pm

Thanks. Got it!!! I understand the technique now.