Correct output but it's showing error

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#1

This is the question
** **Crte a function called every_three_nums that has one parameter named start .

The function should return a list of every third number between start and 100 (inclusive). For example, every_three_nums(91) should return the list [91, 94, 97, 100] . If start is greater than 100 , the function should return an empty list.**

This is my solution

def every_three_nums(start):
  if start < 100:
    lst = list(range(start, 101, 3))
    return lst
  else:
    lst = []
    return lst

print(every_three_nums(91))

While this produces the correct answer I’m getting a error

every_three_nums(100) should have returned [100] , and it returned

Can you guys help? what’s wrong here?

#2

Consider step by step, line by line, what happens in your function if start = 100

You can briefly try your code outside a function if you like ,which should help you pick up on the minor error.

1 Like
#3

Hey! Here’s a solution that doesn’t involve a loop (which hasn’t been reviewed yet) or writing two different functions.

def every_three_nums(start):
  if (start <= 100):
    return [start] + every_three_nums(start + 3)
  else:
    return []

print(every_three_nums(91))