Confused and stuck in creating and adding parameters to a function

homework
offsite

#1

def  manipulate_data(type,data):
    if type=='list':
        list=[1,4,9,16,25]:
            return list.reverse
    elif type=='set':
        set={"a", "b", "c", "d", "e"}:
            item.add("ANDELA"):
            item.add("TIA"):
            item.add("AFRICA"):
            return set.result
    elif type=='dictionary':
        dictionary={"bread": 14, "grapes": 30, "biscuit": 8, "sugar": 16}:
            return dictionary.keys

#2

@bodeayeni,

the FUNCTION talk

def myFunc( param1, param2):
    # Begin of =myFunc= FUNCTION-BODY
    # this =myFunc= function- has 2 PARAMETERS param1 and param2
    # param1 and param2 PARAMETERS are used 
    # as -local- VARIABLES throughout the =myFunc= FUNCTION-BODY
    print( param1 + " and " + param2 )
    #End of =myFunc= FUNCTION-BODY

If you want to call/execute the myFunc function
you will have to add a pair of parentheses to myFunc
like
myFunc()
As the myFunc function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren")

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**


#3

@bodeayeni,

++++ function with 1 parameter using return-statement

def myFunction( param1 ):
    # //Begin of =myFunction= FUNCTION-BODY
    # //=myFunction= function has 1 PARAMETER param1
    # //this param1 PARAMETER is used as a -local- VARIABLE
    # //throughout the =myFunction= FUNCTION-BODY
    return param1;
    # //End of FUNCTION-BODY

You have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the =myFunction= FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 )

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the print-method to do a display.

theResult = myFunction( 4 )
print theResult

OR directly

print myFunction( 4 )

#4

Thank you for your reply i ran the code below again and still having error.

def manipulate_data(string,data)
def manipulate_data(list,[1,4,9,16,25]
    if string=='list':
        return[25,16,9,4,1]
    elif string=='set':
        add("ANDELA+"TIA"+"AFRICA")
        return("ANDELA,"TIA","AFRICA")
    elif string=='dictionary':
        return{1:'d',2:'i',3:'c',4:'t',5:'i',6:'o',7:'n',8:'a',9:'r',10:'y'}
    else:
      raise value error

My question is this "How do i make a function behaves differently"?


#5

@bodeayeni,

After a google search
python determine argument of function site:stackoverflow.com
and reading
= http://stackoverflow.com/questions/2225038/determine-the-type-of-an-object
( also check right-hand RELATED-Link column )
= http://stackoverflow.com/questions/847936/how-can-i-find-the-number-of-arguments-of-a-python-function?lq=1

def a_function(parameter):
    #determine type of parameter
    if isinstance(parameter,list):
        print "parameter is a =list="
    elif isinstance(parameter,dict):
        print "parameter is a =dict="
    elif isinstance(parameter,str):
        print "parameter is a =string="
    else:
        print "what kind of parameter is this ???" + str(type(parameter))

#call the function with an ARGUMENT
a_function([])
a_function({})
a_function('string')
a_function(12)
a_function(1.23)

=================================================

= http://stackoverflow.com/questions/19985145/how-do-i-create-a-python-set-with-only-one-element
!!= http://stackoverflow.com/questions/1952464/in-python-how-do-i-determine-if-an-object-is-iterable


#6

Thank you for your swift response,i think im getting somewhere now,here is my code below.

def manipulate_data(string,data):
    #accepts string  and manipulate data
    if string=='list':
        return"list.reverse"
    elif string=='set':
        set.add("ANDELA")
        set.add("TIA")
        set.add("AFRICA")
        return set.result
    elif string=='dictionary':
        return dictionary.keys 
   
#call the function with an ARGUMENT
manipulate_data(list,[25,16,9,4,1])
manipulate_data(set,{"ANDELA","TIA","AFRICA"})
manipulate_data(dictionary,{'apples': 23, 'oranges': 15, 'mangoes': 3, 'grapes': 45})

But im getting this error after running it,

"Traceback (most recent call last):
File "prog.py", line 16, in
NameError: name 'dictionary' is not defined"
Im stuck again ,dont know what that means,
And here is the question below,

Create a function manipulate_data that does the following,Accepts as the first parameter a string specifying the data structure to be used "list", "set" or "dictionary,Accepts as the second parameter the data to be manipulated based on the data structure specified e.g [1, 4, 9, 16, 25] for a list data structure.
*Based off the first parameter
return the reverse of a list or add items "ANDELA", "TIA" and "AFRICA" to the set and return the resulting set
* return the keys of a dictionary.


#7

@bodeayeni,
The Instructions:
Create a function manipulate_data that does the following,

  • Accepts as the first parameter a string
    specifying the data structure to be used "list", "set" or "dictionary",
  • Accepts as the second parameter the data to be manipulated
    • based on the data structure specified as first-parameter
      e.g [1, 4, 9, 16, 25] for a list data structure.
      *Based on the first parameter
      • return the reverse of a list
        or
      • add items "ANDELA", "TIA" and "AFRICA" to the set and return the resulting set
        or
      • return the keys of a dictionary
def manipulate_data(string,data):
    #return type(data)
    print data
    #accepts string  and manipulate data
    if string=='list':
        print type(data)
        print list(reversed(data))
        return list(reversed(data))
    elif string=='set':
        data.add("tia")
        #set.add("TIA")
        #set.add("AFRICA")
        return data
    elif string=='dictionary':
        '''
        return type(data)
        '''
        #return type(data)
        return data.keys()
        print "i am dict"

#call the function with an ARGUMENT
print(manipulate_data('list',[6,25,16,9,4,1]))
print(manipulate_data('set',{"ANDELA","TIA","AFRICA"}))
print(manipulate_data('dictionary',{'apples': 23, 'oranges': 15, 'mangoes': 3, 'grapes': 45}))
print(manipulate_data('set',{"ANDELA1","TIA1","AFRICA1"}))

( PS. You cleanup the mess !!! )

Reference

Used google search
builtin functions site:python.org
https://docs.python.org/2/library/functions.html#
python reversing list site:stackoverflow.com
http://stackoverflow.com/questions/3940128/how-can-i-reverse-a-list-in-python
http://stackoverflow.com/questions/16819222/how-to-return-dictionary-keys-as-a-list-in-python-3-3