# Conditionals & Control Flow Error

#1

So my code isn't working and this is the message it gave me.
My code:
def the_flying_circus():
if the_flying_circus():
return true
elif the_flying_circus():
return false
else:
print "LOL"

``````3 < 4
bool_one = True and True``````

Error MEssage:
Oops, try again. The following exception was raised when calling the_flying_circus(): RuntimeError: maximum recursion depth exceeded

#2

@scriptjumper50299,
You are calling the_flying_circus() function from within it-self...time again and again
until you reached the MAXIMUM Recursion depth.....!!!

The Instructions:
Write an if statement in the_flying_circus(). It must include:
01. if, elif, and else statements;
02. At least one of and, or, or not;
03. A comparator (==, !=, <, <=, >, or >=);
04. Finally, the_flying_circus() must return True when evaluated.

Thus

``````def the_flying_circus():
if 8 > 9:    # Start coding here!
print "I don't understand"
# the code inside this block!
elif 6 > 9:
print "I still don't understand"
# You'll want to add the else statement, too!
else:
return 8 == 8``````

#3

### the FUNCTION talk

``````def myFunc( param1, param2):
# Begin of =myFunc= FUNCTION-BODY
# this =myFunc= function- has 2 PARAMETERS param1 and param2
# param1 and param2 PARAMETERS are used
# as -local- VARIABLES throughout the =myFunc= FUNCTION-BODY
print( param1 + " and " + param2 )
#End of =myFunc= FUNCTION-BODY``````

If you want to call/execute the myFunc function
you will have to add a pair of parentheses to myFunc
like
myFunc()
As the myFunc function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren")

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++ function with 1 parameter using return-statement

``````def myFunction( param1 ):
# //Begin of =myFunction= FUNCTION-BODY
# //=myFunction= function has 1 PARAMETER param1
# //this param1 PARAMETER is used as a -local- VARIABLE
# //throughout the =myFunction= FUNCTION-BODY
return param1;
# //End of FUNCTION-BODY``````

You have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the =myFunction= FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 )

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

#### ============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the print-method to do a display.

``````theResult = myFunction( 4 )
print theResult``````

OR directly

``print myFunction( 4 )``

#4

Wow! Thanks for helping me! I'm just learning how to program and now I understand more. thanks again