Computer choice Part 2

var userChoice = prompt(“Do you choose rock, paper or scissors?”);
var computerChoice = Math.random();
console.log (computerChoice);
if (computerChoice <= 0.33) {
return “Rock”;
};
else if (computerChoice <= 0.66) {
return “Paper”;
};
else (computerChoice >= 0.67) {
return “Scissors”;
};

I cannot see the problem for the life of me and have tried several variations. Please help!

No semicolons after conditional statements see this link for an explanation:


and no condition after else.

I’m still having trouble it’s now saying illegal return statement.

I’ve removed the semicolons from the conditional statements and the condition from the else but still having trouble.

var userChoice = prompt(“Do you choose rock, paper or scissors?”);
var computerChoice = Math.random();
console.log (computerChoice);
if (computerChoice <= 0.33) {
return “Rock”
};
else if (computerChoice <= 0.66) {
return “Paper”
};
else {
return “Scissors”
};

The semicolons are still there and yes return is a keyword that is only allowed in function, so as there is no function there should not be any return. Afaik the instructions want you to assign a new value to computerChoice and not to return it.

1 Like

Thanks I got it now.

But Guyzz, How to use the between operations in if statement?

Is my approach correct??

`var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
console.log(computerChoice);
if(computerChoice<=0.33)
{
    computerChoice="rock";
}
else if(computerChoice>=0.34,computerChoice<=0.66) 
{
    computerChoice="paper"
}
else(computerChoice>=0.67,computerChoice<=1.00)
{
    computerChoice="scissors"
}`

Can I use for the if conditions??

Instead of a comma to join the parameters use && - that means “and” and will check that both the conditions are true.

1 Like

okay so I have:

var userChoice = prompt("Do you choose rock, paper or scissors?") var computerChoice = Math.random(); console.log(computerChoice); if (computerChoice <=.33) { return "rock" }else if{ (computerChoice>=0.34 && computerChoice<=0.66) return "paper" }else if{ (computerChoice >=.67) return "scissors" }

Can anyone help me understand what I did wrong? I looked at everyone else's responses and modified my result through that but It still says that there was a problem with my syntax.

Your condition is actually correct the problem is that you messed up with the () and {} its:

if(condition){
    code
}
else if(other condition){
    code
}
else [if(yet another condition)]{
    code
}