CODE CHALLENGES: INTERMEDIATE JAVASCRIPT sortSpeciesByTeeth()

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#1


i had create a code of the SpeciesByTeeth() project like this :

const speciesArray = [ {speciesName:'shark', numTeeth:50}, {speciesName:'dog', numTeeth:42}, {speciesName:'alligator', numTeeth:80}, {speciesName:'human', numTeeth:32}];

// Write your code here:

const sortSpeciesByTeeth = (array) => {

 

  return array.sort(parseInt(species.numTeeth, 10))  

}

for sorts the array in ascending and sorts the array in ascending order based on the average number of teeth that species possesses ( numTeeth ) but not work correctly can soeone help me

#2

if I look at the docs for the .sort() method (link), I see:

Syntax

arr.sort([compareFunction])

Parameters

compareFunction Optional
Specifies a function that defines the sort order. If omitted, the array elements are converted to strings, then sorted according to each character’s Unicode code point value.

If I then look at the argument you provide:

return array.sort(parseInt(species.numTeeth, 10))

parseInt(species.numTeeth, 10) does not look like a function?

#3

sir please can you explain me how the number can be order in string format

#4

Did the explanation on MDN not help?

there are couple of examples with explanation how such a function would need to work.

#5

Thanks for your help, i will analyse it and resolve it

#6

If you then need further help, let me know :slight_smile: but seems like a good idea to do further reading on how .sort() with compare function works

#7

but if we make an array of species like this :
onst speciesArray = [ {speciesName:‘shark’, numTeeth:50}, {speciesName:‘dog’, numTeeth:42}, {speciesName:‘alligator’, numTeeth:80},{speciesName:‘human’, numTeeth:32},{speciesName:‘human’, numTeeth:9}] added an {speciesName:‘human’, numTeeth:9} in the array ,all the order wiil completly change so 9 will be in the last of order

#8

which means you have two options: re-sort the array after adding elements

or inserting element in the array at the right place.

#9

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#10

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