#Code Challenge #12: June 28, 2017
Every week, we feature the type of brain-teasing question that might be asked in a full-stack developer’s job interview at places such as Google and Facebook.
This week’s challenge was reported to have been asked in interviews at Facebook:
Write a function,
isPermPalindrome, that will test if a given string is a permutation of a palindrome.
Stringconsisting only of lowercase letter characters
trueif the string is a permutation of a palindrome and
falseif the string is not a permutation of a palindrome
isPermPalindrome("kayak") => true
isPermPalindrome("yakak") => true
Permutations are all possible arrangements of a collection of things, where the order is important.
From Merriam Webster, a palindrome is a “word, verse, or sentence (such as “Able was I ere I saw Elba”) or a number (such as 1881) that reads the same backward or forward.” Read more about palindromes here or see some interesting examples here.
#####Find out more about basic challenges.
As above, but
isPermPalindromeshould now be able to account for punctuation, spaces, and capitalization in the input string.
- Your input string may now include spaces, numbers, punctuation, and capitalization, but in assessing whether the string is a palindrome or not, spaces, punctuation, and capitalization does not matter. For example, akyKa is a permutation of Kayak, but we don’t care that there is one upper case
Kand one lower case
kin Kayak – this is still a palindrome.
isPermPalindrome("Science Bros.") => false
#####Find out more about intermediate challenges.
isPermPalindromeas efficiently as possible.
Reply to this thread with a link to your code on repl.it and paste your properly formatted code to participate! Don’t just submit your code, remember to
explain your solution, too! If you want to be considered as the winner, your function
must have the
correct name and provide
output in the format specified above, you also need to abide by our other simple rules.
As always solutions using imports to do all the heavy lifting such as
itertools will not be considered for the winner.
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