i cant figure our whats wrong with my code:

n = [3, 5, 7]

def double_list(x):

for i in range(0, len(n)):

x[i] = x[i] * 2

return x

print double_list(n)

i cant figure our whats wrong with my code:

n = [3, 5, 7]

def double_list(x):

for i in range(0, len(n)):

x[i] = x[i] * 2

return x

print double_list(n)

13/18 list and functions. help?

Call the return outside of the for loop.

```
n = [3, 5, 7]
# Don't forget to return your new list!
def double_list(x):
for i in range(0, len(x)):
x[i] = x[i] * 2
return x
print double_list(n)
```

You are doing this because you first tell the code that for every i in list x in the range 0 to the length of the list (len) to multiply its value by two.

Then you return that amount in step 2. If you put the return in a for loop you basically tell the code to first do multiply in step 1A and then to return the amount in step 1B. That's not logical in this exersize.

my code now returned:

[6, 10, 14]

None

isn't that right?

it still gets an error:

Oops, try again. double_list([0, 1]) resulted in an error: list index out of range

your function should work for multiply lists, look at this code:

```
def double_list(x):
print x
double_list([1,2,3])
double_list([4,5,6])
double_list([7,8,9])
```

see how `x`

contains every list. the argument (lists) gets passed to the function parameter (in this case `x`

)

you should loop over `x`

so your function works for multiply lists, instead of one fixed lists.

it finally worked! but i still dont get why it was wrong though I got the same result.

the exercise will validate if your code works correctly by calling your function with different lists, your function could only handle one lists

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