Can we describe what this is?

def knts_to_mps(k):
    return k / 1.944

def t_from_h(h):
    return (h / 4.9) ** 0.5

def drop(h, k):
    return knts_to_mps(k) * t_from_h(h)

>>> drop(1000, 200)

This version is free of dependencies:

def drop(h, k):
    f = lambda x: x / 1.944
    g = lambda x: (x / 4.9) ** 0.5
    return f(k) * g(h)

>>> drop(1000, 200)

Surprised there is no answer to this question, yet. Come on, don’t be shy!

Toss it. This is what it is…

A bomb dropped from a plane traveling 200 knots at 1000 meters altitude needs to be released 1500 meters ahead of the target. It will take around 15 seconds to hit the ground traveling at 100 m/s forward and 140 m/s downward. We need to resolve those two vectors to get a complete picture of the momentum, mv, but needless, the destruction will be weighed on the type of munition. There will be enough momentum to set off any kind of final charge.


Just hope the plane reaches the distance and altitude it needs to escape the blast of whatever it delivered. Those fifteen seconds would be h e l l on the pilot, as would be the next thirty.

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