Break outside Loop?


#1



File "python", line 26
SyntaxError: 'break' outside loop


Just curious as to why the break is outside the loop ? Shouldn't the break terminate the loop after printing 'no' ? My objective is ideally to have the program print an error message and end program if user input were not to be an integer.


from random import randint

board = []

for x in range(0, 5):
    board.append(["O"] * 5)

def print_board(board):
    for row in board:
        print " ".join(row)

print_board(board)

def random_row(board):
    return randint(0, len(board) - 1)

def random_col(board):
    return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
guess_row = raw_input("Guess Row:")
guess_col = raw_input("Guess Col:")
if guess_row == str(guess_row) or guess_col == str(guess_col):
    print "NO." 
    break 

print ship_row
print ship_col

# Write your code below!
if guess_row == ship_row and guess_col == ship_col:
    print "Congratulations! You sank my battleship!"
    
else:
    if guess_row not in range(len(board)) or guess_col not in range(len(board)):
        print "Oops, that's not even in the ocean."
    elif guess_row == guess_row and guess_col == guess_col:
        print "You guessed that one already."
    
    else:
        print "You missed my battleship!"
        board[guess_row][guess_col] = "X"
        print_board(board)


#2

@lustwerk an If- statement only runs once (if it isn't inside a loop), so it doesn't need break- statements to stop running. Loops are another thing, because they can execute the code multiple times.


#3

This topic was automatically closed 7 days after the last reply. New replies are no longer allowed.