Hi community. I’d like to share my solution to the Python Block Letters Exercise that uses more than just print(). I ended up doing this because I was just revisiting the career path to tackle what was added, without really knowing what the learner was expected to know at that point. Also, I wanted to try out using a Codebyte.
# Alexander Z Lacson
# Ive learned that money is everything
def printrow(A_locs:list, char):
row_out = [" "]*5
for index in range(len(row_out)):
if index in A_locs:
index
row_out[index] = char
concatenated_row_out = ''.join(row_out)
return(concatenated_row_out)
def printascii(letters:list, char_list:list):
for col in range(7):
for each, char in zip(range(len(letters)), char_list):
print(printrow(letters[each][col], char) + " ", end="")
print("")
letter_A = [
[2],
[1, 3],
[0, 4],
list(range(5)),
[0, 4],
[0, 4],
[0, 4],
]
letter_Z = [
list(range(5)),
[4],
[3],
[2],
[1],
[0],
list(range(5)),
]
letter_L = [[0]]*6 + [list(range(5))]
letters = [letter_A, letter_Z, letter_L]
char_list = ["A", "Z", "L"]
printascii(letters, char_list)
The output of the codebyte doesn’t match the output in the exercise. So, here’s a snip showing the proper output:
To understand the code:
-
printrowis a function that prints out a row of a letter. -
printasciiserves as the “main function”. It takes a list of letter coordinates and letter characters and prints them out side by side. It makes us ofprintrow. - The position in the grid where each character will be inserted is defined for each letter.
- The ascii character of each letter, in the proper order, is defined as a list.
To add more letters, simply declare the positions of a new letter and then add the ascii character of that letter to char_list.
