We are given some completed examples to work with:

```
one = 0b1
two = 0b10
three = 0b11
four
five
six
seven
eight
nine
ten
eleven
twelve
```

Note that there no quotes on the values, only the prefix, `0b`

that tells the compiler to treat these as binary numbers.

`0b1`

is obviously `1`

(one). Since there are only two digits in the binary number system, we can only work with 1's and 0's to represent our numbers.

Study the table in the instructions to see how the values of each bit double as we move to the left.

`0b1`

shifted left, gives, `0b10`

, which is 2 * 1, or 2 to the first power. Shift to the left again, we get, 0b100, or 4, which is 2 * 2, or 2 to the second.

Just as in decimal, a left shift multiplies the digit by 10, in binary it is 2.

The number 12 is less than 16, so will be represented in 4 bits or less.

```
2^3 + 2^2 + 2^1 + 2^0 == 8 + 4 + 2 + 1 == 15 == 0b1111
8 + 4 + 0 + 0 == 12 == 0b1100
```

You should be able to complete this list with this knowledge in hand.