# A Real Win | Problem

#1

``````from random import randint

board = []

for x in range(5):
board.append(["O"] * 5)

def print_board(board):
for row in board:
print " ".join(row)

print "Let's play Battleship!"
print_board(board)

def random_row(board):
return randint(0, len(board) - 1)

def random_col(board):
return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
print ship_row
print ship_col

# Everything from here on should go in your for loop!
# Be sure to indent four spaces!

for turn in range(4):
print "Turn", turn + 1
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))

if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sunk my battleship!"
break
else:
if (guess_row < 0 or guess_row > 4) or (guess_col < 0 or guess_col > 4):
print "Oops, that's not even in the ocean."
elif(board[guess_row][guess_col] == "X"):
print "You guessed that one already."
else:
print "You missed my battleship!"
board[guess_row][guess_col] = "X"

if turn == 3:
print "Game Over"
# Print (turn + 1) here!
print_board(board)

It says that the problem is:``````

File "python", line 37
else:
^
SyntaxError: invalid syntax

#2

Why is there an error? Because `else` should be preceded by `if`. You have to increase indentation level of `break` statement, it should be inside the `if`:

``````if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sunk my battleship!"
break
else:``````

Now you will get this error:

SyntaxError: 'break' outside loop

This is your whole `for` loop:

``````for turn in range(4):
print "Turn", turn + 1``````

rest of the code is outside the loop, is this correct? Nope. I think that you should be able to fix this problem without our help

Hint - indentations are important.

#3

Thank you very much! It worked!

#4

Great! You're very welcome

#5

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