Why am I not able to print just odd numbers. I don't understand what I am supposed to do or how to get it there. I get that the number is being divided and then the remainder if equal to 0 is skipped. So do I just have to find a number that skips all even numbers?

# 9.9 Next Method

Javascript has the so-called **modulo** / **remainder**-*operator* if used it will **return** the **rest-value**.

**9%3** You read it as nine modulo three is **zero**, as 9 divided by 3 has **NO rest-value**.**22%6** You read 22 modulo six is **4**, as 22 divided by 6 will leave you with **rest-value 4****16%8** You read it as sixteen modulo eight is **zero**, as sixteen divided by 8 has **NO rest-value**.

Now for the exercise 2/33:

```
var multiplesOfEight = [8,16,24,32,40,58];
| | | | | |
multiplesOfEight[0] | | | | |
multiplesOfEight[1] | | | |
multiplesOfEight[2] | | |
multiplesOfEight[3] | |
multiplesOfEight[4] |
multiplesOfEight[5]
```

multiplesOfEight[0] --> 8

multiplesOfEight[2] --> 24

multiplesOfEight[5] --> 58

multiplesOfEight[0]%8 --> 8%8 --> 0

multiplesOfEight[2]%8 --> 24%8 --> 0

multiplesOfEight[5]%8 --> 58%8 --> 2

*google search*

== the Book ==

javascript remainder operator site:developer.mozilla.org

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Arithmetic_Operators

== discussions / opinions ==

javascript remainder operator site:stackoverflow.com

= http://stackoverflow.com/questions/4467539/javascript-modulo-not-behaving

javascript array site:developer.mozilla.org

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array

**tylerz**#4

for i in 1..5

next if i % 2 == 0

print i

end

Here is the example. but it wants it from 1 to 18 skipping odd numbers. It wants me to skip to the next iteration if the number is odd. And I am in ruby. what you posted earlier I am not that far in. Thank you though for the information. The typed part cleared up what the computer was reading.

**ameyparab**#5

Thats how my code looks like as well. I run into an error as well.

Error: Oops, try again. It looks like your loop doesn't print out the numbers 18 to 0.

for i in 1..5

next if i % 2 == 0

print i

end

What is the solution ?

**tylerz**#6

Excellent question. All I changed was:

for i in 1..18

next if i % 3 == 0

print i

end

I changed it to 3 thinking that if 2 made if print odd numbers then maybe 3 will make it print even numbers.

loool u guys are funny all u had to do was change == to != meaning not equal to

i = 20

loop do

i -= 1

next if i % 2 != 0

print "#{i}"

break if i <= 0

end

Please re-edit your Post

- leave one blank-line above of your code
- select your code in the Post
- then =click= on the </>-symbol-of-this-editor

Your code will then be in a pre-code state

and you will be able to make/present the proper indentations.

or even better use

= http://discuss.codecademy.com/t/using-backticks-to-format-your-code/3697

**uke5tar**#10

Odd numbers are a multiple of two. We want to skip numbers which aren't a multiple of it. As every second integer is a multiple of two and therefore has the remainder equal to 0 we search for the one which have the remainder of 1.

i = 20

loop do

i -= 1

next if i % 2 == 1

print "#{i}"

break if i <= 0

end