# 9/9 help

#1

lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

def average(numbers):
total = sum(numbers)
total = float(total)
total = total / len(numbers)

def get_average(student):
homework = average(student['homework'])
quizzes = average(student['quizzes'])
tests = average(student['tests'])
weighted = (.10 * homework) + (.30 * quizzes) + (.60 * tests)
return weighted

if score >= 90:
return "A"
elif score >= 80:
return "B"
elif score >=70:
return "C"
elif score >= 60:
return "D"
else:
return "F"

def get_class_average(students):
results = []
for student in students:
results.append(get_average(student))
return average(results)
def get_class_average(students):
results = []
for student in students:
get_average(student)
results = student.append(get_average)
return average(results)
students = [lloyd, alice, tyler]
print get_class_average(students)

File "python", line 57
SyntaxError: 'return' outside function

im so confused

#2

return isn't inside the function because it doesn't have the 4 spaces infront of it. Example;

``````def double(n):
return 2*n <- return is outside function

def double(n):
return 2*n <- now it is and works as intended``````