8. What if choice 1 is scissors


#1

Someone please help, I can not see what is wrong with my code.

var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
computerChoice = "rock";
} else if(computerChoice <= 0.67) {
computerChoice = "paper";
} else {
computerChoice = "scissors";
} console.log("Computer: " + computerChoice);

var compare = function(choice1, choice2)
{
if(choice1 === choice2)
{
return"The result is a tie!";
}
else if (choice1==="rock")
{
if(choice2==="scissors")
return"rock wins";
}
else
{
return"paper wins";
}
}
else if (choice1==="scissors"){
if(choice2==="rock")
return"rock wins";
}
else{
return"sciccors wins";
}
else if (choice1==="paper")
{
if(choice2==="rock")
return"paper wins";
}
else{
return"rock wins";
}
};

compare(userChoice,computerChoice);


#2

@danielmslater,
You are forgetting 1 closing-curly-bracket-} to close the ELSE-IF

else if (choice1==="scissors"){
      if(choice2==="rock")
          return"rock wins";
      }
      else{
          return"sciccors wins";
      }
}

The same for choice1 ==="paper"
as you will need 3 closing-curly-brackets-} in a row
2 for the ELSE-IF IF ELSE structure
1 to close the =compare= FUNCTION-BODY

Please read
http://www.codecademy.com/forum_questions/559dcb4be39efe550f00006b
and concentrate on:

  • the creation of the compare function
  • the truth-table
  • the build of the IF ELSE-IF statement structure as part of the compare FUNCTION-BODY
  • the execution of the compare function (keeping in mind that the return statement is used )