8. Part of the Whole Error: Needs Integer and not String


#1

<PLEASE USE THE FOLLOWING TEMPLATE TO HELP YOU CREATE A GREAT POST!>

<Below this line, add a link to the EXACT exercise that you are stuck at.>
https://www.codecademy.com/courses/python-beginner-en-qzsCL/1/4?curriculum_id=4f89dab3d788890003000096
<In what way does your code behave incorrectly? Include ALL error messages.>
Oops, try again. get_class_average([alice]) resulted in an error: list indices must be integers, not str
<What do you expect to happen instead?>
Not sure how to make it print an integer and not string.

```python

lloyd = {
“name”: “Lloyd”,
“homework”: [90.0, 97.0, 75.0, 92.0],
“quizzes”: [88.0, 40.0, 94.0],
“tests”: [75.0, 90.0]
}
alice = {
“name”: “Alice”,
“homework”: [100.0, 92.0, 98.0, 100.0],
“quizzes”: [82.0, 83.0, 91.0],
“tests”: [89.0, 97.0]
}
tyler = {
“name”: “Tyler”,
“homework”: [0.0, 87.0, 75.0, 22.0],
“quizzes”: [0.0, 75.0, 78.0],
“tests”: [100.0, 100.0]
}

Add your function below!

def average(numbers):
total = sum(numbers)
total = float(total)
return float(total) / len(numbers)

def get_average(student):
homework = average(student[“homework”]) * 0.1
quizzes = average(student[“quizzes”]) * 0.3
tests = average(student[“tests”]) * 0.6
avefinal = ( homework + quizzes + tests)
return avefinal

def get_letter_grade(score):
if score >= 90:
return “A”
elif score >=80:
return “B”
elif score >= 70:
return “C”
elif score >= 60:
return “D”
else:
return “F”
a = get_average(tyler)
print get_letter_grade(a)

def get_class_average(students):
results =
for student in students:
get_average(student)
results.append(get_average(student))
return get_average(results)

<do not remove the three backticks above>

#2

@20dannyb,
What are you doing here

        get_average(student)
        results.append(get_average(student))

AND
then
as you have 1 list =results=
you are using that =list= as an argument
in a call on the get_average() function…!!!


#3

I too have the same problem - can anyone help?

lloyd = {
“name”: “Lloyd”,
“homework”: [90.0, 97.0, 75.0, 92.0],
“quizzes”: [88.0, 40.0, 94.0],
“tests”: [75.0, 90.0]
}
alice = {
“name”: “Alice”,
“homework”: [100.0, 92.0, 98.0, 100.0],
“quizzes”: [82.0, 83.0, 91.0],
“tests”: [89.0, 97.0]
}
tyler = {
“name”: “Tyler”,
“homework”: [0.0, 87.0, 75.0, 22.0],
“quizzes”: [0.0, 75.0, 78.0],
“tests”: [100.0, 100.0]
}

Add your function below!

def average(numbers):
total = sum(numbers)

return float(total) / len(numbers)

def get_average(student):
homework = average(student[“homework”])
quizzes = average(student[“quizzes”])
tests = average(student[“tests”])
return homework * 0.1 + quizzes * 0.3 + tests * 0.6

def get_letter_grade(score):
if score >= 90:
return ‘A’
elif score >= 80:
return ‘B’
elif score >= 70:
return ‘C’
elif score >= 60:
return ‘D’
else:
return ‘F’

get_letter_grade(get_average(lloyd))

def get_class_average(students):
results =
for n in students:
results.append(get_average(students))
return average(results)


#4

@leonhard.wettengmx.n

Yes but…How do I make it give me an integer and not a string…?


#5

@20dannyb,
Instead of calling the get_average() function
you should be calling the average() function…


#6

@leonhard.wettengmx.n

Okay, that solved my problem and passes #8. But it returns the exact same thing. Whether I call the get_average() function or the average() function, I get C printed in the console. How does that make sense? It’s the same exact letter in the console but codecademy says one is wrong and one isn’t. Explain please


#7

hey, not sure what your problem is but I see one error in your get_class_average definition
this:

should use n variable and not students as you are looping by n


#8

@20dannyb,
Please post the FULL code you are using now…
and mention the EXACT Oops or Error message you are getting…
and mention the course section we are now writing about…