can’t seem to get this one, I get an unexpected token error?
if function quarter(number) {
return number/4
console.log(“The statement is true”)
}
else {
console.log(“The statement is false”)
}
can’t seem to get this one, I get an unexpected token error?
if function quarter(number) {
return number/4
console.log(“The statement is true”)
}
else {
console.log(“The statement is false”)
}
function quarter(number) {
return number/4
}
Here you will have to follow the instructions
if ( quarter(12) %3 === 0) {
console.log("The statement is true")
}
else {
console.log("The statement is false")
}
var myFunc = function( param1, param2) {
//Begin of anonymous FUNCTION-BODY
//VARIABLE -myFunc- has an -anonymous function- assigned
//this -anonymous function- has 2 PARAMETERS param1 and param2
//param1 and param2 PARAMETERS are used
//as -local- VARIABLES throughout the FUNCTION-BODY
console.log( param1 + " and " + param2 ) ;
//End of anonymous FUNCTION-BODY
};
If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES “Alena” and “Lauren”
like
myFunc(“Alena”,“Lauren”);
some quotes from the outer-world:
argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block
OR
"parameters" are called “formal parameters”,
while “arguments” are called “actual parameters”.
++++ function with 1 parameter using return-statement
var myFunction = function( param1 ) {
//Begin of FUNCTION-BODY
//myFunction =function= has 1 PARAMETER param1
//this param1 PARAMETER is used as a -local- VARIABLE
//throughout the FUNCTION-BODY
return param1;
//End of FUNCTION-BODY
};
you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.
If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a “number VALUE” 4
myFunction( 4 );
some quotes from the outer-world:
argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block
OR
"parameters" are called “formal parameters”,
while “arguments” are called “actual parameters”.
As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.
var theResult = myFunction( 4 );
console.log( theResult );
OR directly
console.log( myFunction( 4 ) );
@leonhard_wettengmx_n you have a lot of knowledge oh wise one (IDK I’m being weird)
I continue to receive an “unexpected token function” error message based on my code. I have manipulated the first line of code since this is where I declared the function. How else can I change this to let the computer know to quarter the parameter?
var function quarter(number) {
return number/4;
if ( quarter(12) %3 === 0 ) {
console.log(“The statement is true”);
} else {
console.log(“The statement is false”);
}
quarter(12);
If you use the syntax
var myFunction = function() {};
You are actually assigning a so-called anonymous function to the variable myFunction.
You can only use the functionality of myFunction AFTER the definition.
There is however
a second posibillity…
=defining= a so-called named Function
and you would do that with
function myFunction() { }
( no semi-colon-; needed )
Javascript has 2 phases if execute code
Now if you have used the named Function syntax
the function is hoisted
meaning it is put up-front during the parse phase
and thus you are able to use the function
before it is seen in your code…
http://stackoverflow.com/questions/336859/var-functionname-function-vs-function-functionname?rq=1
#may this code will help you guys
var quarter = function(number){
return number/4;
}
if (quarter(12) % 3 === 0 ) {
console.log(“The statement is true”);
} else {
console.log(“The statement is false”);
}
thanks that was veryy usefefulll