8. Functions if else

Get Help JavaScript
#1

can’t seem to get this one, I get an unexpected token error?

if function quarter(number) {
return number/4
console.log(“The statement is true”)
}
else {
console.log(“The statement is false”)
}

#2

@methodjumper78342,

function quarter(number) {
    return number/4
}

Here you will have to follow the instructions

if ( quarter(12) %3 === 0) {
 console.log("The statement is true")
} 
else {
 console.log("The statement is false")
}
1 Like
#3

@methodjumper78342,

the FUNCTION talk

var myFunc = function( param1, param2) {
       //Begin of  anonymous FUNCTION-BODY
       //VARIABLE -myFunc- has an -anonymous function- assigned
       //this -anonymous function- has 2 PARAMETERS param1 and param2
       //param1 and param2 PARAMETERS are used 
       //as -local- VARIABLES throughout the FUNCTION-BODY

      console.log( param1 + " and " + param2 ) ;

      //End of anonymous FUNCTION-BODY
};

If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES “Alena” and “Lauren”
like
myFunc(“Alena”,“Lauren”);

some quotes from the outer-world:

argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block

OR

"parameters" are called “formal parameters”,
while “arguments” are called “actual parameters”.

#4

@methodjumper78342,

++++ function with 1 parameter using return-statement

var myFunction = function( param1 ) {
       //Begin of FUNCTION-BODY
       //myFunction =function= has 1 PARAMETER param1
       //this param1 PARAMETER is used as a -local- VARIABLE
       //throughout the FUNCTION-BODY

      return param1;

      //End of FUNCTION-BODY
      };

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a “number VALUE” 4
myFunction( 4 );

some quotes from the outer-world:

argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block

OR

"parameters" are called “formal parameters”,
while “arguments” are called “actual parameters”.

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

var theResult = myFunction( 4 );
console.log( theResult );

OR directly

console.log( myFunction( 4 ) );
#5

@leonhard_wettengmx_n you have a lot of knowledge oh wise one (IDK I’m being weird)

#6

I continue to receive an “unexpected token function” error message based on my code. I have manipulated the first line of code since this is where I declared the function. How else can I change this to let the computer know to quarter the parameter?

var function quarter(number) {
return number/4;

if ( quarter(12) %3 === 0 ) {
console.log(“The statement is true”);
} else {
console.log(“The statement is false”);
}
quarter(12);

#7

@phedoraj

If you use the syntax

var myFunction = function() {};

You are actually assigning a so-called anonymous function to the variable myFunction.

You can only use the functionality of myFunction AFTER the definition.

There is however
a second posibillity…
=defining= a so-called named Function
and you would do that with

function myFunction() { }

( no semi-colon-; needed )

Javascript has 2 phases if execute code

  • parsing phase the code is loaded and syntax is checked
  • execution phase the loaded code is executed.

Now if you have used the named Function syntax
the function is hoisted
meaning it is put up-front during the parse phase
and thus you are able to use the function
before it is seen in your code…

http://stackoverflow.com/questions/336859/var-functionname-function-vs-function-functionname?rq=1

#8

#may this code will help you guys
var quarter = function(number){
return number/4;
}
if (quarter(12) % 3 === 0 ) {
console.log(“The statement is true”);
} else {
console.log(“The statement is false”);
}

1 Like
#9

thanks that was veryy usefefulll