# 8/9 get_class_average([alice, lloyd]) returned 91.15 instead of 85.85 as expected

#1

get_class_average([alice, lloyd]) returned 91.15 instead of 85.85 as expected

i think the code is good but not go

``````lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

def average(numbers):
total = sum(numbers)
total = float(total)
total = total / len(numbers)

def get_average(student):
homework = average(student['homework'])
quizzes = average(student['quizzes'])
tests = average(student['tests'])
return 0.1 * homework + 0.3 * quizzes + 0.6 * tests

if score >= 90:
return "A"
elif score >= 80:
return "B"
elif score >= 70:
return "C"
elif score >= 60:
return "D"
else :
return "F"

def get_class_average(students):
results = []

for student in students:
results.append(get_average(student))
return average(results)``````

#2

`return` statement in the `get_class_average` function is inside the `for` loop. It means that it will be executed in the first iteration of the loop.

In other words, for `students = [alice, lloyd]` your function will calculate `get_average(alice)` and will append calculated result to the `results` list and will immediately return average value of `results`. `lloyd` has been simply omitted in the calculations.

`return` should be outside the `for` loop/

#3

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