# 7. Return Keyword problem

<PLEASE USE THE FOLLOWING TEMPLATE TO HELP YOU CREATE A GREAT POST!>

<Below this line, add a link to the EXACT exercise that you are stuck at.>

<In what way does your code behave incorrectly? Include ALL error messages.>
“Oops, try again. It looks like you didn’t print out the value of newNumber”

```

Replace this line with your code.
// Parameter is a number, and we do math with that parameter
var timesTwo = function(number) {
return number * 2;
};

// Call timesTwo here!
var newNumber = timesTwo(“8”);
console.log(newNumber);

``````<do not remove the three backticks above>

It's weird because the correct answer logged in the console``````
1 Like

### the FUNCTION talk

``````var myFunc = function( param1, param2) {
//Begin of  anonymous FUNCTION-BODY
//VARIABLE -myFunc- has an -anonymous function- assigned
//this -anonymous function- has 2 PARAMETERS param1 and param2
//param1 and param2 PARAMETERS are used
//as -local- VARIABLES throughout the FUNCTION-BODY

console.log( param1 + " and " + param2 ) ;

//End of anonymous FUNCTION-BODY
};
``````

If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES “Alena” and “Lauren”
like
myFunc(“Alena”,“Lauren”);

some quotes from the outer-world:

argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block

OR

"parameters" are called “formal parameters”,
while “arguments” are called “actual parameters”.

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

### function with 1 parameter using return-statement

``````var myFunction = function( param1 ) {
//Begin of FUNCTION-BODY
//myFunction =function= has 1 PARAMETER param1
//this param1 PARAMETER is used as a -local- VARIABLE
//throughout the FUNCTION-BODY

return param1;

//End of FUNCTION-BODY
};
``````

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a “number VALUE” 4
myFunction( 4 );

some quotes from the outer-world:

argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block

OR

"parameters" are called “formal parameters”,
while “arguments” are called “actual parameters”.

#### ============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

``````var theResult = myFunction( 4 );
console.log( theResult );
``````

OR directly

``console.log( myFunction( 4 ) );``

Thanks for the detailed reply, but it’s still not working even after those two suggestions

@ajaxsurfer54191
Well what is the code you are using now…
and what is the message you are receiving…

var newNumber = timesTwo(8);
console.log(newNumber);

hey ajax, found the solution, when passing 8, it should be as a value not a string, just remove the “”

2 Likes

I used your code and my code and revised it a little and came up with this and it worked.

// Parameter is a number, and we do math with that parameter
var timesTwo = function(number) {
return number * 2;
};

// Call timesTwo here!
timesTwo(8);
var newNumber = timesTwo(“8”);
console.log(newNumber);

Here’s my code:
// Parameter is a number, and we do math with that parameter
var timesTwo = function(number) {
return number * 2;
};

// Call timesTwo here!
timesTwo(8);
var newNumber = timesTwo(“8”);
console.log(newNumber);

When I submit it I get “TypeError: console.log is not a function” I can’t figure out what I did wrong

Nevermind, I refreshed the page and it worked.