7. Return Keyword problem


#1



https://www.codecademy.com/courses/javascript-beginner-en-6LzGd/1/2?curriculum_id=506324b3a7dffd00020bf661


"Oops, try again. It looks like you didn't print out the value of newNumber"


Replace this line with your code. 
// Parameter is a number, and we do math with that parameter
var timesTwo = function(number) {
    return number * 2;
};

// Call timesTwo here!
var newNumber = timesTwo("8");
console.log(newNumber);

It's weird because the correct answer logged in the console


#2

@ajaxsurfer54191,

the FUNCTION talk

var myFunc = function( param1, param2) {
       //Begin of  anonymous FUNCTION-BODY
       //VARIABLE -myFunc- has an -anonymous function- assigned
       //this -anonymous function- has 2 PARAMETERS param1 and param2
       //param1 and param2 PARAMETERS are used 
       //as -local- VARIABLES throughout the FUNCTION-BODY

      console.log( param1 + " and " + param2 ) ;

      //End of anonymous FUNCTION-BODY
};

If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren");

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

function with 1 parameter using return-statement

var myFunction = function( param1 ) {
       //Begin of FUNCTION-BODY
       //myFunction =function= has 1 PARAMETER param1
       //this param1 PARAMETER is used as a -local- VARIABLE
       //throughout the FUNCTION-BODY

      return param1;

      //End of FUNCTION-BODY
      };

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 );

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

var theResult = myFunction( 4 );
console.log( theResult );

OR directly

console.log( myFunction( 4 ) );

#3

Thanks for the detailed reply, but it's still not working even after those two suggestions


#4

@ajaxsurfer54191
Well what is the code you are using now.....
and what is the message you are receiving...


#5

Answer Below:

var newNumber = timesTwo(8);
console.log(newNumber);


#6

hey ajax, found the solution, when passing 8, it should be as a value not a string, just remove the ""


#7

I used your code and my code and revised it a little and came up with this and it worked.

// Parameter is a number, and we do math with that parameter
var timesTwo = function(number) {
return number * 2;
};

// Call timesTwo here!
timesTwo(8);
var newNumber = timesTwo("8");
console.log(newNumber);


#8

Here's my code:
// Parameter is a number, and we do math with that parameter
var timesTwo = function(number) {
return number * 2;
};

// Call timesTwo here!
timesTwo(8);
var newNumber = timesTwo("8");
console.log(newNumber);

When I submit it I get "TypeError: console.log is not a function" I can't figure out what I did wrong


#9

Nevermind, I refreshed the page and it worked.