7/9 "What if choice1 is paper?"


#1

var compare = function(choice1, choice2) {
    if(choice1 === choice2) {
        return "The result is a tie!";
    } else if(choice1 === "paper") {
        
    } if(choice2 === "rock") {
        return "paper wins";
    } else {
        return "scissors wins";
        
    } else if(choice1 === "rock") {
        
    } if(choice2 === "scissors") {
        return "rock wins";
    } else {
        return "paper wins";
    }
};

what is wrong?


#2

Those if-else statements should probably be in those else if statememnts


#3

I found that the way you put that was quite comical. tips tophat


#4

Hi @minusgix

You have to close your :
else if(choice1 === "paper"){ //after else{return "scissors wins"} }
and
else if(choice1 === "rock"){ //after else{return "paper wins"} }

And you must add an other else if(choice1 === "scissors") to have full of condition possible.

Hold on :wink:


#5

var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
computerChoice = "rock";
} else if(computerChoice <= 0.67) {
computerChoice = "paper";
} else {
computerChoice = "scissors";
} console.log("Computer: " + computerChoice);

var compare = function(choice1, choice2) {
if (choice1 === choice2) {
return "The result is a tie!"
}
else if (choice1 === "rock") {
if (choice2 === "scissors") {
return "rock wins";
}

else {
return "paper wins";
}

}
else if (choice1 === "paper") {
if (choice2 === "rock" ) {
return "paper wins"
}
else {
return "scissors wins"
}
}}

Look over your code and see if it matches mine, also mine is correct.