 # 6/15 what is wrong?

cubes_by_four=[x3,for x in range(1,11) if (x3)%4==0]
print cubes_by_four

this line

``````cubes_by_four=[x**3,for x in range(1,11) if (x**3)%4==0]
``````

should be

``````cubes_by_four=[x**3 for x in range(1,11) if (x**3)%4==0]# no comma before the for
``````
``````cubes_by_four = [x**3 for x in range(1, 11) if x**3 % 4 == 0]
print cubes_by_four``````

ERROR

cubes_by_four = [c3 in range(1,11) if (c3)%4 == 0]

print cubes_by_four

File “python”, line 1
cubes_by_four = [c3 in range(1,11) if (c3)%4 == 0]
^
SyntaxError: invalid syntax

???

Your code should rather be this

``````cubes_by_four = [c**3 for c in range(1,11) if (c**3)%4 == 0]
#                     ^<->^
#                     missing that
#                     for statement
#                     with c as the iterator
``````

I did the way I use to work out the cube numbers back in school. it worked though:

``````cubes_by_four = [x*x*x for x in range(1,11) if (x*x*x) % 4 == 0]

print cubes_by_four``````

I just curious… the instruction said `1 through 10 only`, but here we wrote like this `range(1,11)` rather than `range(1,10)` …any one can explain ?

@textrunner60544 take a look at this post it explains the range function
thanks @rydan …it helps me… 