5. Finding that special someone


#1

I can't seem to see what is wrong with my code-- I did call the search function, but it is saying "Bob Jones" isn't being logged to the console. ?


Error Message: "Oops, try again. It looks like your search function didn't log "Bob Jones" to the console. Did you remember to call search after you defined it?"


var bob = {
    firstName: "Bob",
    lastName: "Jones",
    phoneNumber: "(650) 777-7777",
    email: "bob.jones@example.com"
};

var mary = {
    firstName: "Mary",
    lastName: "Johnson",
    phoneNumber: "(650) 888-8888",
    email: "mary.johnson@example.com"
};

var contacts = [bob, mary];

function printPerson(person) {
    console.log(person.firstName + " " + person.lastName);
}

function list() {
	var contactsLength = contacts.length;
	for (var i = 0; i < contactsLength; i++) {
		printPerson(contacts[i]);
	}
}

function search(lastName) {
    var contactsLength = contacts.length;
    for (var i =0; i <contactsLength; i++) {
        if (lastName === contacts[i].lastName) {
            console.log(contacts[i]);
        }
    }
    };
    
search("Jones");


#2

You do have a function that does this. Maybe the SCT is expecting us to use it?


#3

That was it! Thank you!!!!

printPerson(contacts[i]);

instead of

console.log(contacts[i]);


#4

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