Gives me the following error message:
Traceback (most recent call last):
File "python", line 1, in
IOError: [Errno 2] No such file or directory: 'text.txt'
The error is in line 1 which is defined as per the instructions... I expect no error in the code... can someone please explain why the error pops up?
Thanks in advance!
my_file = open("text.txt", "r")
for i in range(1,3):
print my_file.readline()
my_file.close()Don't use a for loop that is why they say on three seperate lines So you would write it like this
my_file = open("text.txt", "r")
print my_file.readline()
print my_file.readline()
print my_file.readline()
my_file.close()I'm the first line of the file!
I'm the second line.
Third line here, boss.
these lines are already there
Change the text. And then run the code but it has to be three lines of text like this,
I tried this, and I still get the below error.
Traceback (most recent call last):
File "python", line 1, in
IOError: [Errno 2] No such file or directory: 'text.txt'
That worked for me, thanks!
All I did was insert one word into the first line. I didn't even delete the pre-populated text.
Writing something in the text.txt tab worked for me when nothing else did. Thank you.
Just for future reference instead of looping with a traditional count controlled loop you can loop through the file like you would a string or an array like this:
my_file = open( "text.txt", "r" )
for line in my_file:
print( line )
my_file.close()This way when you don't know how many lines are in the file you can still iterate through them all.
Bandit, it says On three separate lines, print out the result of calling my_file.readline(). which is referring to the result that will be printed in the console, not your code. It's more efficient to use a loop here.