4. Syntax Problem


#1



My code seems fine to me but it won't accept it and it's driving me crazy! 
Can anyone help? Here's the error message: Oops, try again. It looks like 
you didn't put quotes around the food you gave foodDemand!

var foodDemand = funtion(food); {
    console.log("I want to eat" + " " + food);
};
foodDemand("apples")


#2

@imlinxnotyou,
For the Javascript interpreter
a semi-colon-; is an End-of-Statement indicator...
This would lead to your foodDemand() function
to be interpreted as

var foodDemand = function(food);

and only if you had correctly used function instead of your function
Remove the semi-colon...AND change the funtion

the FUNCTION talk

var myFunc = function( param1, param2) {
       //Begin of  anonymous FUNCTION-BODY
       //VARIABLE -myFunc- has an -anonymous function- assigned
       //this -anonymous function- has 2 PARAMETERS param1 and param2
       //param1 and param2 PARAMETERS are used 
       //as -local- VARIABLES throughout the FUNCTION-BODY

      console.log( param1 + " and " + param2 ) ;

      //End of anonymous FUNCTION-BODY
};

If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren");

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

function with 1 parameter using return-statement

var myFunction = function( param1 ) {
       //Begin of FUNCTION-BODY
       //myFunction =function= has 1 PARAMETER param1
       //this param1 PARAMETER is used as a -local- VARIABLE
       //throughout the FUNCTION-BODY

      return param1;

      //End of FUNCTION-BODY
      };

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 );

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

var theResult = myFunction( 4 );
console.log( theResult );

OR directly

console.log( myFunction( 4 ) );

#3

@leonhard.wettengmx.n

I am very confused by all that. Can you please just tell me how to fix my code so I can continue with the lessons?


#4

@imlinxnotyou,

var foodDemand = function(food) {
    console.log("I want to eat" + " " + food);
};

#5

leonhard is OLDSCHOOL! What up Leon. What's up with the two plus signs? I can enter only 1 argument and return a value.


#6

It's "function" i guess you spelled it wrong.


#7

I figured out my plus sign problem.