4. digit_sum


hi everyone, im having (i guess) some concept issues appearing in this excercise, the code is:

1. if i replace the return lista for print lista, the code works ok, instead if i leave the return, the code dont work. (i have no idea why xD)
2. in a for loop, what if i want to return the value AND also print it in console?

def digit_sum(n):
    for i in n_str:
    return lista  #this is the problem print instead of return works well, i dont know why that logic
    for i in lista:
    return suma
    print suma  #can i do something like this?


One of the qualities of the return statement is that it will cause an =immediate EXIT= of the function.
It also return's a result with NO-Display

Now as you want both the lista and the suma to be =returned=
you have to think about a mechanism to keep track of those Value's
You could for instance use

def digit_sum(n):
    #create an EMPTY dictionary
    dummy_dict = {};
    dummy_dict["argument"] = n;
    for i in n_str:
    print lista; 
    for i in lista:
    print suma;  
    #prepare return
    dummy_dict["lista"] = lista;
    dummy_dict["suma"] = suma;
    return dummy_dict;

#capture the =return= Value in a VARIABLE
result = digit_sum(24);
print result;
print result["argument"]
print result["lista"]
print result["suma"]
#you could create the =string= inside of function & return =string=
print("Digit sum of {0} via list {1} is {2}".format(


Since your return is not conditional, all the code that follows will never we seen.

Given that you are not mutating the string you made from n, we can simply iterate over the string and add each value.to an accumulator variable. No need for a list.

    suma = 0
    for i in n_str:
        suma += i
    return suma

print digit_sum(1234)    # 10