Hello, guys! I would like to hear your opinion about the solution for this task I am struggling to make. I am sure that is not the easiest way what I am trying to do, but I would love to accomplish this task using mathematics (I remember similar task when I was in High School, however now I can't do that same way).

- digit_sum

So, basically what I am trying to achieve is to represent an integer in the following shape:

n= 10^(i)*n1+10^(i-1)*n2+...+10^0*nj

where sum=n1+n2+...+n(j)

```
sum=0
n_len=len(str(n))
i=n_len
while i<=(n_len) and i!=1:
digit=n//(10**(i-1))
#Here is I can't really figure out the next iteration...
#Maybe it's better to use exponent here
return n, sum
i-=1
if i==1:
sum+=n % (10**(i-1))
return sum
print digit_sum(434)
```

Please, I am sure you guys know the solution. I won't be able to sleep unless I find the way