This is what I've done:
def distance_from_zero(zero):
if type(zero) == int or type(zero) == float:
return abs(zero)
else:
return "Nope"
Can anyone tell me what I did wrong and what I should have done?
19/19 Help
boosheeboy
#1
ionatan
#2
In what way is it not acting like you want? And what does does your code really look like? Mind the formatting.
itw_w
#3
Try out the identation.
def distance_from_zero(n):
if type(n) ==int or type(n) == float:
return abs (n)
else:
return "Nope"
cafreen
#6
So why can't I also get a correct response using the following code?
def distance_from_zero(x):
if type(x) == str:
return "Nope"
else:
return abs(x)
kesar13
#7
def distance_from_zero(n):
if type(n) == int or type(n) == float:
return abs(n)
else:
return "Nope"Worked for me. it was about formatting. Add the required 4 spaces before if and return 
natividadf
#8
This is what worked for me. Make sure the spaces in your if statement are correct or you may return an error. Good luck.
baci_tracin
#9
hi, can someone please tell me what i am doing wrong? this is my code:
def distance_from_zero(n):
** if type(n) == int or type(n) == float:**
** return abs()**
** else:**
** return 'nope'**
and the error message down below is:
Ops, tente outra vez.
** It looks like you have a TypeError. Make sure your function should **
only take one input. (Or check the error message for more info.) - abs()
** takes exactly one argument (0 given)**
baci_tracin
#10
sorry let me rewrite that
hi, can someone please tell me what i am doing wrong? this is my code:
*def distance_from_zero(n):
if type(n) == int or type(n) == float:
return abs()
else:
return 'nope'*and the error message down below is:
- Ops, tente outra vez.
It looks like you have a TypeError. Make sure your function should
only take one input. (Or check the error message for more info.) - abs()
takes exactly one argument (0 given) *