17/19


#1

This is the code I have:
from random import randint

indent preformatted text by 4 spaces

board = []

for x in range(5):
board.append(["O"] * 5)

def print_board(board):
for row in board:
print " ".join(row)

print "Let's play Battleship!"
print_board(board)

def random_row(board):
return randint(0, len(board) - 1)

def random_col(board):
return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
print ship_row
print ship_col

Everything from here on should go in your for loop!

Be sure to indent four spaces!

guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))

if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sunk my battleship!"
break
else:
if (guess_row < 0 or guess_row > 4) or (guess_col < 0 or guess_col > 4):
print "Oops, that's not even in the ocean."
elif(board[guess_row][guess_col] == "X"):
print "You guessed that one already."
else:
print "You missed my battleship!"
board[guess_row][guess_col] = "X"
if turn == 3:
print "Game Over"
# Print (turn + 1) here!
print_board(board)

for turn in range(0, 4):
turn = 0
print "Turn", turn + 1

Whenever I try to input this I always get " 'break' outside loop" and I have no idea why.


#2

@stevew1113
Yes you can only use the break statement inside a loop like the while loop but not in the if/elif/else block.
example usage

print ("Hit 'x' to terminate")
answer = raw_input("what is the name of this site: ")
while(True):
    if(answer.lower() == "codeacademy" or answer.lower() == "x" ):
        break
    answer = raw_input("what is the name of this site: ")

so you should take away the break statement here

if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sunk my battleship!"
break# take away

#3

rydan is correct. In this context you need

for i in range(4):

at the part where it says "Everything from here on should go in your for loop!"