# 17/19 help with breaking my code

#1

File "python", line 33
SyntaxError: 'break' outside loop

I wanted it to work so it would break my code when someone wins it doesn't repeat

``````from random import randint

board = []

for x in range(5):
board.append(["O"] * 5)

def print_board(board):
for row in board:
print " ".join(row)

print "Let's play Battleship!"
print_board(board)

def random_row(board):
return randint(0, len(board) - 1)

def random_col(board):
return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
print ship_row
print ship_col

# Everything from here on should go in your for loop!
# Be sure to indent four spaces!
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))

if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sunk my battleship!"
break
else:
if (guess_row < 0 or guess_row > 4) or (guess_col < 0 or guess_col > 4):
print "Oops, that's not even in the ocean."
elif(board[guess_row][guess_col] == "X"):
print "You guessed that one already."
else:
print "You missed my battleship!"
board[guess_row][guess_col] = "X"
# Print (turn + 1) here!
for turn in range(4):
print turn + 1
print_board(board)
if turn == 3:
print "Game Over"``````

#2

`# Everything from here on should go in your for loop!`

#3

I tried indenting everything, I think it is counted as young in the for loop. When I unindent my break so its on the same level as the if statement then the problem goes away, but it says there is a syntax error with my else statement right below it.

#4

Look where your for loop starts, and where it is supposed to start.

#5

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