17/19 Functions


#1

I'v reviewed my code and cannot see what is wrong with it, It may be an indention error?

def shut_down(s):
return shut_down

if s== "yes" :
return "Shutting down"
elif s=="no":
return "Shutdown aborted"
else:
return "sorry"


#2

@basechase,
Please read the function talk
and keep in mind that using the return statement
a =result= is returned
AND
the function is immediately EXITED.....!!!

the FUNCTION talk

def myFunc( param1, param2):
    # Begin of =myFunc= FUNCTION-BODY
    # this =myFunc= function- has 2 PARAMETERS param1 and param2
    # param1 and param2 PARAMETERS are used 
    # as -local- VARIABLES throughout the =myFunc= FUNCTION-BODY
    print( param1 + " and " + param2 )
    #End of =myFunc= FUNCTION-BODY

If you want to call/execute the myFunc function
you will have to add a pair of parentheses to myFunc
like
myFunc()
As the myFunc function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren")

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++ function with 1 parameter using return-statement

def myFunction( param1 ):
    # //Begin of =myFunction= FUNCTION-BODY
    # //=myFunction= function has 1 PARAMETER param1
    # //this param1 PARAMETER is used as a -local- VARIABLE
    # //throughout the =myFunction= FUNCTION-BODY
    return param1;
    # //End of FUNCTION-BODY

You have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the =myFunction= FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 )

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the print-method to do a display.

theResult = myFunction( 4 )
print theResult

OR directly

print myFunction( 4 )

#3
def shut_down(s):
    return shut_down

if s== "yes" :
    return "Shutting down"
elif s=="no":
    return "Shutdown aborted"
else:
    return "sorry"

Okay, so your problem is that your if/elif/else statement is outside the function. It needs to be INSIDE the function. (See how I bolded that? It is very important. :smiley: ) Make it look like this:

def shut_down(s):
    return shut_down
    if s== "yes" :
        return "Shutting down"
    elif s=="no":
        return "Shutdown aborted"
    else:
        return "sorry"

Just make sure you know what you are doing! :slight_smile: Happy Coding!


#4

Could you explain why you need return shut_down under def shut down(s): ?


#5

That means to know what you are saying for s. I am pretty sure.