# 16. Game Over

#1

<PLEASE USE THE FOLLOWING TEMPLATE TO HELP YOU CREATE A GREAT POST!>

<Below this line, add a link to the EXACT exercise that you are stuck at.>

<In what way does your code behave incorrectly? Include ALL error messages.>

File “python”, line 47
if turn = 3:
^
SyntaxError: invalid syntax

**

<What do you expect to happen instead?>
I’m unsure of what to do, can someone point me in the right direction… thanks!
**

```python

from random import randint

board = []

for x in range(5):
board.append([“O”] * 5)

def print_board(board):
for row in board:
print " ".join(row)

print "Let’s play Battleship!"
print_board(board)

def random_row(board):
return randint(0, len(board) - 1)

def random_col(board):
return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
print ship_row
print ship_col

# Be sure to indent four spaces!

for turn in range(4):
print “Turn”, turn + 1
guess_row = int(raw_input(“Guess Row:”))
guess_col = int(raw_input(“Guess Col:”))

if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sunk my battleship!"
else:
if (guess_row < 0 or guess_row > 4) or (guess_col < 0 or guess_col > 4):
print "Oops, that’s not even in the ocean."
elif(board[guess_row][guess_col] == “X”):
print "You guessed that one already."
else:
print "You missed my battleship!"
board[guess_row][guess_col] = “X”
# Print (turn + 1) here!
print (turn + 1)
print_board(board)
if turn = 3:
print “Game Over”

``<do not remove the three backticks above>``

#2

a single equal sign means assign, why would you do this in a if condition? Shouldn’t you check if turn equals 3?

#3

True, I forgot about that thanks!

#4