# 14. Test run, what if it's not an int?

#1

Hey guys! So after a little trial and error I managed to figure out a really inefficient way of figuring out if the input was an integer or not and of it wasn't telling the user as such. However I was wondering anyone could guide me on an easier way to do this, keep in mind Im still learning and I may have completely approached this incorrectly.
CODE CODE CODE
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```````from random import randint

board = []

for x in range(0, 5):
board.append(["O"] * 5)

def print_board(board):
for row in board:
print " ".join(row)

print_board(board)

def random_row(board):
return randint(0, len(board) - 1)

def random_col(board):
return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)

try:
guess_row = int(raw_input("Guess Row:")) -1
except ValueError:
guess_row = "Not an integer"

try:
guess_col = int(raw_input("Guess Col:")) -1
except ValueError:
guess_col = "Not an integer"

print ship_row
print ship_col

if guess_row == ship_row and guess_col == ship_col:
print "Congratulations you sank my battleship!"
else:
if guess_row == "Not an integer" or guess_col == "Not an integer":
print "You should learn how to read!"
elif guess_row not in range(5) or guess_col not in range(5):
print "Oops, that's not even in the ocean."
elif board[guess_row][guess_col] == 'X':
print "You guessed that one already."
else:
print "You missed my battleship!"
board [guess_row][guess_col] = "X"
print_board(board)```````

#2

To test for whether the input is an integer or not, you can use Python's built in `type()` function. You can use the below format to try to test it.

``````if type(guess_row) == int:
# Some code!``````

I hope this works for your purposes...

#3

I am trying to debug my program and its throwing this error (IndexError: list index out of range) if I enter a number that's off board. Everything else is working perfect.