# 13 - how to solve this?

#1

How to solve this case? I tried all things. Thanks.

// here we define our method using "this", before we even introduce bob
var setAge = function (newAge) {
this.age = newAge;
};
// now we make bob
var bob = new Object();
bob.age = 30;
// and down here we just use the method we already made

// change bob's age to 50 here

bob.setAge = setAge
setAge(50)

`

#2

@pen1onet.pl,
Try by using

bob.setAge(50)

#3

but it errors:
TypeError: bob.newAge is not a function

#4

@methodninja66349

The Method is named setAge
and the PARAMETER of this setAge() Method is =newAge=

As you call the bob.setAge() Method
you will have to provide an argument
in this case a number Value 50
bob.setAge(50)

### the FUNCTION talk

var myFunc = function( param1, param2) {
//Begin of  anonymous FUNCTION-BODY
//VARIABLE -myFunc- has an -anonymous function- assigned
//this -anonymous function- has 2 PARAMETERS param1 and param2
//param1 and param2 PARAMETERS are used
//as -local- VARIABLES throughout the FUNCTION-BODY

console.log( param1 + " and " + param2 ) ;

//End of anonymous FUNCTION-BODY
};

If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren");

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

### function with 1 parameter using return-statement

var myFunction = function( param1 ) {
//Begin of FUNCTION-BODY
//myFunction =function= has 1 PARAMETER param1
//this param1 PARAMETER is used as a -local- VARIABLE
//throughout the FUNCTION-BODY

return param1;

//End of FUNCTION-BODY
};

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 );

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

#### ============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

var theResult = myFunction( 4 );
console.log( theResult );

OR directly

console.log( myFunction( 4 ) );