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#1

I do not understand instructions. so I can't write code.
help me


#2

print filter(lambda x: x=="Python", languages)


#3

Thanks for the Answer


#4

That actually does not answer the question. That answer simply makes x == "Python" and basically ignores languages... At least as far as I can tell.

print filter(lambda x: x == languages[2], languages)

...might be better, though I'm not sure this even properly utilizes the rest of the code (filter and lambda)

On the upside, both this and the earlier reply will give you a "Go" on this.


#5

print filter(lambda x: x==languages[2],languages)...:smile:
try this