12 Bad aim


#1

I get this mistake: "Oops, try again.
Make sure you print "Oops, that's not even in the ocean." if the user guesses a row or column that is off the board.
"

Can you help me see my mistake?

from random import randint

board = []

for x in range(0, 5):
board.append(["O"] * 5)

def print_board(board):
for row in board:
print " ".join(row)

print_board(board)

def random_row(board):
return randint(0, len(board) - 1)

def random_col(board):
return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))

print ship_row
print ship_col

Write your code below!

if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sank my battleship!"
else:
if guess_row not in range(5) or guess_col not in range(5):
print "Oops, that's not even in the ocean"
else:
print "You missed my battleship!"
board[guess_row][guess_col] = 'X'
print_board(board)


9/9 Unexpected Indent
#2

Your code:

else:
    if guess_row not in range(5) or guess_col not in range(5):
        print "Oops, that's not even in the ocean"

The code that will work:

else:
    if guess_row not in range(5) or guess_col not in range(5):
        print "Oops, that's not even in the ocean."

Can you spot the difference..? :wink:


#3

Haha! Thanks a lot!
Very intolerant set-up :smile:


#4

Can some one help me ... I can't understand what's wrong with it
else:
if guess_row not in range(5) or guess_col not in range(5):
print "Oops, that's not even in the ocean."

it says "File "python", line 39
else:
^
SyntaxError: invalid syntax"


#5

if im not wrong, youre meant to intend tha if sentence, or use an elif, but im not sure...


#6

Full stop after ocean makes the difference. Due to the absence of (.) the server is not able to verify. Write the exact thing that shows in error description.


#7

thanks.ooooooooooooo