# 11. Count - is it possible to make less coding?

#1

I solved the Lesson, but I think the answer could be done with less effort. Any suggestions on how to make a less code lines?

def count(sequence, item):
if type(sequence) == str:
counter = 0
for y in sequence:
if y == item:
counter +=1
return counter

elif type(sequence) == list:
counter = 0
for y in sequence:
if y == item:
counter +=1
return counter
else:
c = 0
for x in str(sequence):
if x == str(item):
c+= int(x)
return c

#2

well, your code for strings and lists is exactly the same? The requirement of the exercise are more then is actually validated, this:

def count(sequence, item):
counter = 0
for y in sequence:
if y == item:
counter +=1
return counter

is enough to pass the exercise

#3

def count(sequence, item):
return sequence.count(item)

This is also enough to pass the exercise

#4

yea, of course you can solve the problem with built in functions, but it is not as much fun

#5

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