11.8 . Not getting proper Output


#1

lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

Add your function below!

def average(numbers):
total=float(sum(numbers))
total=float(total/len(numbers))
return total
student=[lloyd,alice,tyler]
def get_average(student):
homework=average(student["homework"])
quizzes=average(student['quizzes'])
tests=average(student['tests'])
return .1*homework+.3*quizzes+.6*tests

def get_letter_grade(score):
score=float(score)
if(score >= 90):
return "A"
elif(score >= 80):
return 'B'
elif(score >= 70):
return 'C'
elif(score >= 60):
return 'D'
else:
return "F"

print get_letter_grade(get_average(lloyd))

results=[]
def get_class_average(student):
for stud in student:
results.append(get_average(stud))
return average(results)

My error : Oops, try again. get_class_average([lloyd]) returned 85.85 instead of 80.55 as expected


#2

In this part:
def get_letter_grade(score):
score=float(score)
if(score >= 90):
return "A"
elif(score >= 80):
return 'B'
elif(score >= 70):
return 'C'
elif(score >= 60):
return 'D'
else:
return "F"

The "A" and the "F" needs to change to 'A' and 'F'


#3

i got the same thing when results.append command was not indented in the for stud in students loop